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Problemas Diseno circuitos/problema_1.asc

+Version 4
+SHEET 1 888 772
+WIRE 256 16 224 16
+WIRE 544 16 336 16
+WIRE -64 112 -64 96
+WIRE 16 112 -64 112
+WIRE 16 128 16 112
+WIRE 224 144 224 16
+WIRE 224 144 160 144
+WIRE 304 144 224 144
+WIRE -64 160 -64 112
+WIRE 544 160 544 16
+WIRE 544 160 368 160
+WIRE 640 160 544 160
+WIRE 160 176 160 144
+WIRE 304 176 288 176
+WIRE 544 192 544 160
+WIRE 160 304 160 256
+WIRE 288 304 288 176
+WIRE 288 304 160 304
+WIRE 160 352 160 304
+WIRE 544 464 544 272
+WIRE 160 480 160 432
+FLAG 16 128 0
+FLAG 336 192 Vs-
+FLAG -64 240 Vs-
+FLAG -64 16 Vs+
+FLAG 336 128 Vs+
+FLAG 160 480 0
+FLAG 640 160 Vout
+IOPIN 640 160 Out
+FLAG 544 464 0
+SYMBOL OpAmps\\LT6201 336 160 R0
+SYMATTR InstName U1
+SYMBOL voltage -64 0 R0
+WINDOW 123 0 0 Left 0
+WINDOW 39 0 0 Left 0
+SYMATTR InstName V2
+SYMATTR Value 5
+SYMBOL voltage -64 144 R0
+WINDOW 123 0 0 Left 0
+WINDOW 39 0 0 Left 0
+SYMATTR InstName V3
+SYMATTR Value 5
+SYMBOL res 352 0 R90
+WINDOW 0 0 56 VBottom 2
+WINDOW 3 32 56 VTop 2
+SYMATTR InstName R2
+SYMATTR Value 10k
+SYMBOL res 560 288 R180
+WINDOW 0 36 76 Left 2
+WINDOW 3 36 40 Left 2
+SYMATTR InstName R3
+SYMATTR Value 20k
+SYMBOL current 160 176 R0
+WINDOW 3 -64 97 Left 2
+WINDOW 123 0 0 Left 0
+WINDOW 39 0 0 Left 0
+SYMATTR InstName iin
+SYMATTR Value 0
+SYMBOL res 144 336 R0
+SYMATTR InstName R1
+SYMATTR Value 10k
+TEXT -98 344 Left 2 !.tran 2
+TEXT -136 520 Left 2 ;Usando ley de voltajes de k. \n-Vin + Iin*R2 + Iin*R1 = 0\n-Vin + Iin (R2+R1) = 0\nIin (R2+R1)=Vin\nR2+R1=Vin/Iin=20 v/mA\nEntonces tomo a R1=R2=10k de tal forma que 20k/1mA=20 v