diff --git a/ejercicio2.ipynb b/ejercicio2.ipynb index 40660f11ef2d6b5f08948c30c2d37494e84b7cfe..2025b8c51f478836096665edee3658856f813a88 100644 --- a/ejercicio2.ipynb +++ b/ejercicio2.ipynb @@ -12,17 +12,18 @@ ] }, { - "attachments": {}, "cell_type": "markdown", "metadata": {}, "source": [ "## Resolución (1)\n", "Los valores para el triángulo de Pascal pueden ser encontrados mediante la siguiente fórmula:\n", - "$$\\left(\\begin{array}{l}\n", + "\n", + "$\\left(\\begin{array}{l}\n", "n \\\\\n", "r\n", "\\end{array}\\right)=\\frac{n !}{r !(n-r) !}\n", - "$$\n", + "$\n", + "\n", "Donde n representa el número de la fila, r el número de la columna.\n", "- Validamos si el número ingresado es un entero, con un **if().**\n", "- Utilizamos las fórmula para encontrar los valores para la fila n-esima y mediante el uso de un **for()**." @@ -30,7 +31,7 @@ }, { "cell_type": "code", - "execution_count": 8, + "execution_count": 15, "metadata": {}, "outputs": [], "source": [ @@ -87,7 +88,7 @@ }, { "cell_type": "code", - "execution_count": 14, + "execution_count": 16, "metadata": {}, "outputs": [ { @@ -145,19 +146,19 @@ }, { "cell_type": "code", - "execution_count": 12, + "execution_count": 18, "metadata": {}, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ - "[[1, 4, 6, 4, 1], [1, 5, 10, 10, 5, 1], [1, 6, 15, 20, 15, 6, 1], [1, 7, 21, 35, 35, 21, 7, 1], [1, 8, 28, 56, 70, 56, 28, 8, 1], [1, 9, 36, 84, 126, 126, 84, 36, 9, 1], [1, 10, 45, 120, 210, 252, 210, 120, 45, 10, 1], [1, 11, 55, 165, 330, 462, 462, 330, 165, 55, 11, 1]]\n" + "[[1, 4, 6, 4, 1], [1, 5, 10, 10, 5, 1], [1, 6, 15, 20, 15, 6, 1], [1, 7, 21, 35, 35, 21, 7, 1], [1, 8, 28, 56, 70, 56, 28, 8, 1], [1, 9, 36, 84, 126, 126, 84, 36, 9, 1], [1, 10, 45, 120, 210, 252, 210, 120, 45, 10, 1]]\n" ] } ], "source": [ - "entrada(4,5,6,7,8,9,10,11)" + "entrada(4,5,6,7,8,9,10)" ] }, {